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Windows Server 2022 版本 21H2 官方正式版ISO镜像

MVS订阅中心简体中文版(含标准版、标准桌面体验版、数据中心版、数据中心桌面体验版)
64位版本:Windows Server 2022 Standard、Windows Server 2022 Standard (Desktop Experience)、Windows Server 2022 Datacenter、Windows Server 2022 Datacenter (Desktop Experience) (4in1) (x64) - DVD (Chinese-Simplified)
文件名称: zh-cn_windows_server_version_2022_updated_sep_2021_x64_dvd_b4b9f360.iso(4.88G)
SHA-256: C63B9B982467E2A097F8BE510885B91B8BCC81C3E0767FEDEC0D878789515858

ed2k://|file|zh-cn_windows_server_version_2022_updated_sep_2021_x64_dvd_b4b9f360.iso|5239418880|F683A7A81A87B17552AD3F31AD667633|/

VLSC订阅中心简体中文版(含标准核心版、标准数据中心核心版) //批量授权
64位版本:Windows Server Standard Core 2022、Windows Server Datacenter Core 2022 (2in1) (x64) - DVD (Chinese-Simplified)
文件名称: zh-cn_windows_server_version_2022_updated_sep_2021_x64_dvd_d125a8d5.iso(4.88G)
SHA-256: 4D137F19764982F23D8660F83A842A106D43C9B6B4C13055C176947473ADF3ED

ed2k://|file|zh-cn_windows_server_version_2022_updated_sep_2021_x64_dvd_d125a8d5.iso|5240166400|1F8B4C146B58ABC2C142C259F6B122B4|/

[windows10] WINDOWS 10 2022年5月17

Windows 10 (business editions), version 21H2 (updated May 2022) (x64) - DVD (Chinese-Simplified)

ed2k://|file|zh-cn_windows_10_business_editions_version_21h2_updated_may_2022_x64_dvd_3e40125e.iso|5804613632|7E0B252E786FA54ADCCD0D24D1BA943A|/

Windows 10 (consumer editions), version 21H2 (updated May 2022) (x64) - DVD (Chinese-Simplified)

ed2k://|file|zh-cn_windows_10_consumer_editions_version_21h2_updated_may_2022_x64_dvd_97a670d9.iso|5928056832|68D43DA9180BB68671F185694219749D|/

Windows 10 Enterprise LTSC 2021 (x64) - DVD (Chinese-Simplified)

ed2k://|file|SW_DVD9_WIN_ENT_LTSC_2021_64BIT_ChnSimp_MLF_X22-84402.ISO|5044211712|1555B7DCA052B5958EE68DB58A42408D|/

BigDecimalDemo 数学相关

package 数学相关类;

import java.math.BigDecimal;

public class BigDecimalDemo
{

        public static void main(String[] args)
        {
                // float和double都不能表示精确的小数,此时使用BigDecimal
                
                // TODO Auto-generated method stub
                System.out.println("0.09 + 0.01 ="+(0.09+0.01));
                System.out.println("1.00 - 0.33 ="+(1.00-0.33));
                
                // 
//                BigDecimal b1 = new BigDecimal(0.09);
//                BigDecimal b2 = new BigDecimal(0.01); 
//                // 0.1 ?
//                System.out.println(b1.add(b2)); 因为在0.09是double类型,创建b1就已经不精确了
                BigDecimal b1 = new BigDecimal("0.09");
                BigDecimal b2 = new BigDecimal("0.01"); 
                System.out.println(b1.add(b2));
                
                BigDecimal b3 = new BigDecimal("0.0123");
                System.out.println(b3.scale());// 4
                
                // 除法
                BigDecimal b4 = new BigDecimal("1.");
                BigDecimal b5 = new BigDecimal("3.00");
//                System.out.println(b4.divide(b5));// 如果是1.0 / 3.0 ,报异常java.lang.ArithmeticException
                
                //divide(b5,有效位数,舍入规则)
                System.out.println(b4.divide(b5,5,BigDecimal.ROUND_FLOOR));
                
//                b4.compareTo(b5) 比较   -1(b6<b7) 0 1(b6>b7)
                BigDecimal b6 = new BigDecimal("3.14");
                BigDecimal b7 = new BigDecimal("3.1450");
                System.out.println(b6.compareTo(b7));
                System.out.println(b6.equals(b7));
                
        }

}

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